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1. zatty (zatnosk@manowar.social)'s status on Wednesday, 12-Jan-2022 14:40:52 UTC zatty

   Why can't I figure out how to generate a "h" and a "C" in JavaScript without string literals or function calls?

   It is possibly impossible.

   • zatty (zatnosk@manowar.social)'s status on Wednesday, 12-Jan-2022 14:40:45 UTC zatty

     in reply to

     • Just Ellie 🐍

     @noelle The primary technique is generating values and then converting them to a string that I then index into to get a letter.

     "c" is generated with ([]+{})[!![]-[]+((!![]+!![])+[])]

     ([]+{}) results in string concatenation between an empty array and an object, which gives me "[object Object]".

     Then that string is indexed into with "12" generated by !![]-[]+((!![]+!![])+[])

     !![]-[] => true - "" => 1 - 0
     !![]+!![] => true+true => 2
     2 + [] => 2 + "" => "2"
     1+"2" => "12"

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   • Just Ellie 🐍 (noelle@chat.noelle.codes)'s status on Wednesday, 12-Jan-2022 14:40:49 UTC Just Ellie 🐍

     in reply to

     @zatnosk I love how obscure this is. How are you getting the other letters?

   • zatty (zatnosk@manowar.social)'s status on Wednesday, 12-Jan-2022 14:40:50 UTC zatty

     in reply to

     Unfortunately, I'm also missing "w" and "P", which would let me write "getOwnPropertyNames", which in turn would let me pull out "getCharCode" without touching "C" or "h".

   • zatty (zatnosk@manowar.social)'s status on Wednesday, 12-Jan-2022 14:40:51 UTC zatty

     in reply to

     If I could generate "h" and "C" from non-letter expressions, then I could remove the last three letters from this source code of an expression that evaluates to my name:

     https://gist.github.com/Zatnosk/4d80a9e72bec6ec3b73a6d0b1443aea7

   • makeworld (makeworld@sunbeam.city)'s status on Friday, 14-Jan-2022 02:51:09 UTC makeworld

     in reply to

     • Just Ellie 🐍

     @zatnosk what you are doing is a solved problem. All of JS can be written with six characters: []()!+

     http://www.jsfuck.com/

     cc @noelle

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